CTC 440 - Homework 5 (Grades/Vertical Curves)

1. If the elevation at STA 12+25 is 473.10' and the elevation at STA 18+22 is 482.36', what is the grade between the two points?

2. If the elevation at STA 173+00 is 379.00' and the grade ahead is +5.2% what will the elevation be at STA 181+00?

3. Compute the centerline elevations (at 50' intervals) for the following vertical curve:

Crest Curve (+5% ascending and -7% descending)
ELEV=107.00 ft at STA 2+00
PVC STA =3+00
PVT STA=11+00
PVI STA=7+00

Find the station and elevation of the highest point on the curve.

Calculate the elevation at the PVI. Check the curve elevation at the PVI by calculating the middle ordinate E and adding it to the PVI elevation

4. Fit a sag vertical curve on a highway reconstruction project on Main Street, Bedford Falls. The Bedford Falls Community Church is located at STA 8+00. Because of the church driveway, the centerline elevation at the church can be no lower than 100.0 feet. Find the shortest vertical curve (to the nearest 100-foot curve length) which can meet these conditions:

Sag Curve (-5% descending and +2% ascending)
STA 2+00, elev=120.0 feet
PVI STA =9+00